f(x+1)=x^2+3x+5

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Solution for f(x+1)=x^2+3x+5 equation: 


Simplifying
f(x + 1) = x2 + 3x + 5

Reorder the terms:
f(1 + x) = x2 + 3x + 5
(1 * f + x * f) = x2 + 3x + 5
(1f + fx) = x2 + 3x + 5

Reorder the terms:
1f + fx = 5 + 3x + x2

Solving
1f + fx = 5 + 3x + x2

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Reorder the terms:
-5 + 1f + fx + -3x + -1x2 = 5 + 3x + x2 + -5 + -3x + -1x2

Reorder the terms:
-5 + 1f + fx + -3x + -1x2 = 5 + -5 + 3x + -3x + x2 + -1x2

Combine like terms: 5 + -5 = 0
-5 + 1f + fx + -3x + -1x2 = 0 + 3x + -3x + x2 + -1x2
-5 + 1f + fx + -3x + -1x2 = 3x + -3x + x2 + -1x2

Combine like terms: 3x + -3x = 0
-5 + 1f + fx + -3x + -1x2 = 0 + x2 + -1x2
-5 + 1f + fx + -3x + -1x2 = x2 + -1x2

Combine like terms: x2 + -1x2 = 0
-5 + 1f + fx + -3x + -1x2 = 0

The solution to this equation could not be determined.

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